所有栏目

74hc173

作者:爱百科

74hc173是一款 CMOS devices。

74hc173介绍

74hc173是一款 CMOS devices。

FEATURES

•Gated input enable for hold (do nothing) mode

•Gated output enable control

•Edge-triggered D-type register

•Asynchronous master reset

•Output capability: bus driver

•ICC category: MSI

GENERAL DEscriptION

The 74HC/HCT173 are high-speed Si-gate CMOS devices

and are pin compatible with low power Schottky TTL

(LSTTL). They are specified in compliance with JEDEC

standard no. 7A.

The 74HC/HCT173 are 4-bit parallel load registers with

clock enable control, 3-state buffered outputs (Q0 to Q3)

and master reset (MR).

When the two data enable inputs (E1 and E2) are LOW, the

data on the Dn inputs is loaded into the register

synchronously with the LOW-to-HIGH clock (CP)

transition. When one or both En inputs are HIGH one

set-up time prior to the LOW-to-HIGH clock transition, the

register will retain the previous data. Data inputs and clock

enable inputs are fully edge-triggered and must be stable

only one set-up time prior to the LOW-to-HIGH clock

transition.

The master reset input (MR) is an active HIGH

asynchronous input. When MR is HIGH, all four flip-flops

are reset (cleared) independently of any other input

condition.

The 3-state output buffers are controlled by a 2-input NOR

gate. When both output enable inputs (OE1 and OE2) are

LOW, the data in the register is presented to the Qn

outputs. When one or both OEn inputs are HIGH, the

outputs are forced to a high impedance OFF-state. The

3-state output buffers are completely independent of the

register operation; the OEn transition does not affect the

clock and reset operations.

QUICK REFERENCE DATA

GND = 0 V; Tamb = 25 C; tr = tf = 6 ns

Notes

1. CPD is used to determine the dynamic power dissipation (PD in W):

PD = CPD VCC

2 fi (CL VCC

2 fo) where:

fi = input frequency in MHz

fo = output frequency in MHz

(CL VCC

2 fo) = sum of outputs

CL = output load capacitance in pF

VCC = supply voltage in V

2. For HC the condition is VI = GND to VCC

For HCT the condition is VI = GND to VCC 1.5 V

ORDERING INFORMATION

热点导航
教育资讯 知道问答 公考资讯 司法考试 建筑知识 工作范文 大学排名 报考专业 学习方法 句子美文 秒知回答 作业解答 精选答案 知途问学